Question

under root 72-under root 72-under 72-infinity=?

Answer 1

Answer:

let y=√(72+√(72+√(72..........infinity

y=✓(72+y)

y^2-y-72=0

y=(1+√(1+288))/2

similarly X=√(42+√(42.......

x=√(42+x)

x=(1+√(1+168))/2

y-x=(√289 - √169)/2

= (17-13)/2=2

Step-by-step explanation: