Question

under root 8 minus under root 4 minus under root 2
$\sqrt{8 - } \sqrt{4} - \sqrt{2}$
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Answer 1

Answer:

2 is the correct answer

Answer 2

The answer is $\bf \sqrt{8}-\sqrt{4} -\sqrt{2} = \sqrt{2}-2$.

$\sqrt{8}$ can be written as $2\sqrt{2}$

$\sqrt{4}$ can be written as 2.

$\sqrt{2}$ will be written as $\sqrt{2}$.

Hence

$\sqrt{8}-\sqrt{4} -\sqrt{2} = 2\sqrt{2}-2-\sqrt{2}$

$2\sqrt{2}-2-\sqrt{2} = \sqrt{2} - 2$

Therefore $\bf \sqrt{8}-\sqrt{4} -\sqrt{2} = \sqrt{2}-2$.

#SPJ2