Question

under root (x) + under root (x/2) hol 3​

Answer 1

Answer:

(√x + √x/2)³

= (√x + √x/2)²(√x+√x/2)

= (√x)² + (√x/2)² + (2×√x×√x/2) × (√x+√x/2)

= (x + x/4 + x)(√x+√x/2)

= (2x+x/4)(√x+√x/2)

= (8x+x/4)(√x+√x/2)

= (9x/4)(√x+√x/2)