Question

Under roote 29 -under root 10 +under root 216÷under root 36

Answer 1

Step-by-step explanation:

solu;

$\frac{(\sqrt{29} - \sqrt{10} + \sqrt{216} )}{\sqrt{36} }$

= $\frac{\sqrt{29} - \sqrt{10} + \sqrt{2^{2}*2*3^{2}*3 }}{\sqrt{2^{2}*3^{2} } }$

=$\frac{\sqrt{29} - \sqrt{10} +2*3 \sqrt{2*3 }}{2*3}$

=$\frac{\sqrt{29} - \sqrt{10} +6 \sqrt{6 }}{6}$

Now we cannot do anything here so it is the answer.

May this help you.

Thank You!!