Under short-circuit condition, the windings of a transformer having
5% impedance will experience a radial force
(a) 5 times of full load value.
(b) 20 times of full load value.
(c) 25 times of full load value.
(d) 400 times of full load value.
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Answered by
4
Answer:
which of this book question
Answered by
0
Answer:
Under short circuit conditions in transformers the force acting on it is directly proportional to square of current....
we already know that the
F= BIL.
Here B depends on I so Force = I2.
For this given impedance i.e. 5% ; short circuit current will increase to 20 times and,
Hence; 20×20= 400 times the force.
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