Under similar conditions of pressure and temperature 40 ml of slightly moist HCl gas is mixed with 20 ml of NH3 gas . the final volume of the gas at the same temperature and Pressure will be..:-
1)100 ml
2)20ml
3)40ml
4)60ml
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Following stoichiometry 1ml ammonia reacts with same amount of most HCl
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Hey dear,
● Answer -
Final volume = 40 ml
● Explanation -
When HCl & NH3 react, following reaction takes place.
HCl + NH3 --> NH4Cl
1 mol HCl & 1 mol NH3 gives 1 mol NH4Cl
∴ 20 ml HCl & 20 ml NH3 will give 20 ml NH4Cl
Also, 20 ml HCl remains unreacted in this reaction.
Final volume is calculated by -
Final volume = Products formed + Unreacted reactants
Final volume = 20 ml + 20 ml
Final volume = 40 ml
Therefore, final volume of mixture will be 40 ml.
Hope this helps you...
● Answer -
Final volume = 40 ml
● Explanation -
When HCl & NH3 react, following reaction takes place.
HCl + NH3 --> NH4Cl
1 mol HCl & 1 mol NH3 gives 1 mol NH4Cl
∴ 20 ml HCl & 20 ml NH3 will give 20 ml NH4Cl
Also, 20 ml HCl remains unreacted in this reaction.
Final volume is calculated by -
Final volume = Products formed + Unreacted reactants
Final volume = 20 ml + 20 ml
Final volume = 40 ml
Therefore, final volume of mixture will be 40 ml.
Hope this helps you...
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