Question

Under similar conditions oxygen and nitrogen are taken in the same mass. The ratio of their volumes will be

Answer 1

If equal masses of oxygen, hydrogen and methane are taken in a container under identical conditions, what's the ratio of their volume?

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Nissim Raj Angdembay, Writer · Nihilist · To-be-chemist

Answered Sep 2, 2015 · Author has 599 answers and 1.9m answer views

1) Convert the mass into moles (use the formula n=m/Mrn=m/Mr)
Since the masses are equal, you can take the mass as x. So, the number of moles would be:
n(O2)n(O2) = x/32
n(H2)n(H2) = x/2
n(CH4)n(CH4) = x/16

2) Divide the moles by the smallest value
Since under identical conditions, the same number of moles occupy the same volume, you can directly divide by the smallest value. Now, which one is the smallest value? Simple. The one with the largest denominator has the smallest value. For example, 1/25 is smaller than 1/10.

So, x/32 is the smallest.
 (x/32)/(x/32) = 1. 

Similarly, you can do it for the others. This now gives us the ratio of:
1:16:2
O2:H2:CH4O2:H2:CH4

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Answer 2

Hope it helps you....