Question

Under standard conditions the potential for the reaction sn(s) + 2fe3+(aq) → 2fe2+(aq) + sn2+(aq) is

Answer 1

E^0 Fe3+/Fe2+ =0.77V

E^0 Sn2+/Sn= -0.14 

Since cathode is the place where reduction takes place it would have higher reduction potential and also Sn is getting oxidised

E^0 of cell= E cathode - E anode

                =0.77 - -0.14

                 =0.91V