under STP if you collect 3 litre of O2 5 litre of cl2 and 6 litre of H2 which has the highest number of molecules which has the lowest number of molecules
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Answers
Answer :-
6 litre of H₂ has the highest number of molecules (1.56 × 10²³) and 3 litre of O₂ has lowest molecules (8 × 10²²) .
Explanation :-
We have :-
→ Volume of O₂ = 3 L
→ Volume of Cl₂ = 5 L
→ Volume of H₂ = 6 L
________________________________
Under STP conditions, 1 mole of any gas occupies a volume of 22.4 litres .
For Oxygen gas (O₂) :-
⇒ Moles = 3/22.4
⇒ Moles = 0.134
Number of molecules :-
= Moles × Avogadro number
= 0.134 × 6.022 × 10²³
= 0.8 × 10²³
= 8 × 10²²
For Chlorine gas (Cl₂) :-
⇒ Moles = 5/22.4
⇒ Moles = 0.223
Number of molecules :-
= 0.223 × 6.022 × 10²³
= 1.34 × 10²³
For Hydrogen gas (H₂) :-
⇒ Moles = 6/22.4
⇒ Moles = 0.26
Number of molecules :-
= 0.26 × 6.022 × 10²³
= 1.56 × 10²³
Answer:
Solution :-
We have :
- Volume of Oxygen = 3 L
- Volume of Chlorine gas = 5 L
- Volume of Hydrogen = 6 L
As we know that :
1 mole of any gas will occupy a volume of 22.4 L.
☣ Moles of Oxygen Gas :-
➙
➙
☣ Number of molecules in Oxygen Gas :
➙ Number of Molecules = 0.134 × 6.022 × 10²³
➙
☣ Moles of Chlorine Gas :
➙
➙
☣ Number of molecules in Chlorine Gas :
➙ Number of Molecules = 0.223 × 6.022 × 10²³
➙
☣ Moles of Hydrogen Gas :
➙
➙
☣ Number of molecules in Hydrogen Gas :
➙ Number of Molecules = 0.26 × 6.022 × 10²³
➙
Henceforth, the highest number of molecules is hydrogen (1.56 × 10²³ and the lowest number of molecules is oxygen gas (8 × 10²²).