Question

Under the action of a force, a 2 kg body moves such that its position x=t^2/3
x is a function of time t is given by - where xis in metre and tin
second. The work done by the force in first two seconds is​

Answer 1

Answer:

sry the question is not clear

Answer 2

Answer:

Under the action of a force, a 2kg body moves such that its position x as a function of time is given by x=t33 where x is in metre and t in second. The work done by the force in the first two seconds is .