under the action of force a 2kg body moves such
that its a position t' in eters as a functions
of time t in seconds guess tey X = t½
The work done by the force in the first five seconds is
Answers
Answered by
4
Answer:
ɦɛʏʏaaa ❤
Explanation:
v=
dt
dx
=t
2
W=
2
1
mv
2
=
2
1
mt
4
=
2
1
×2×(2)
4
=16J
tɦaռҡs❤
Answered by
0
Answer:16joules
Explanation:
Attachments:
Similar questions