Under the action of given coulombic force the acceleration of an electron is 2.5 into 10 ^ 22 metre by second square then the magnitude of acceleration of a proton under the acceleration of same force is nearly
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as we know; F= ma
for electron:
F = mass of electron X acceleration
F = 9.1*10^(-31) X 2.5*20^22
the force is same for proton also as stated above
so,
F = mass of proton X acceleration
so, acceleration = force/(mass of proton)
hence, acceleration = 9.1*10^(-31) X 2.5*20^22/1.67*10^(-27)
The calculated value matches option 'C'.
I Hope it helps!
for electron:
F = mass of electron X acceleration
F = 9.1*10^(-31) X 2.5*20^22
the force is same for proton also as stated above
so,
F = mass of proton X acceleration
so, acceleration = force/(mass of proton)
hence, acceleration = 9.1*10^(-31) X 2.5*20^22/1.67*10^(-27)
The calculated value matches option 'C'.
I Hope it helps!
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0
Answer:
It is not calculated so plz calculate it
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