under the influence of a force an object of mass 4kg accelerates from 3 metre per second to 6 metre per second in seconds how much work was done on the object during this time
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Answer:
54 j
Explanation:
We can use Newton's 2nd Law to find the magnitude of the force:
F
=
m
a
The acceleration a is the rate of change of velocity:
a
=
Δ
V
t
=
6
−
3
8
=
0.375
x
m/s
2
∴
F
=
4
×
0.375
=
1.5
x
N
The work done is the force x the distance travelled in the direction of the force.
To find the distance travelled during this time we can use:
v
2
=
u
2
+
2
a
s
∴
6
2
=
3
2
+
(
2
×
0.375
×
s
)
36
=
9
+
0.75
×
s
s
=
27
0.75
=
36
x
m
W
=
F
×
s
=
1.5
×
36
=
54
x
J
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