Question

Under the right condition ammonia can be converted to nitrogen monoxide NO, NH3 + O2 =====> NO + H2O
HOW MANY GRAM OF H2O COULD BE FORMED FROM A MIXTURE OF 51g OF NH3 AND 48g OF O2 ? plz tell in detail, otherwise I wouldn't be able to understand.​

Answer 1

no of moles of NH3 = 51/17

= 3

no of moles of O2  = 48/32

=1.5

balancing

4NH3 +  5 O2 =====>  4 NO + 6  H2O

NH3  is limiting reagent

4 mole of NH3 = 6 mole of H2O

3 mole of NH3 = 6*3/4

= 4.5 mole of H2O

mass = 4.5*18

= 81gm of H2O is formed