Question

under the right conditions, hydrogen and oxygen react to from steam. what volume of oxygen would be required to react with excess hydrogen to produce 672 CM ^3 of steam if the volumes are measured at STP​

Answer 1

Explanation:

Balanced equation :

2H2(g) + O2(g) → 2H2O(g)

1 volume of O2(g) produces 2 volumes of H2O(g)

Therefore 672/2 = 336 cm³ O2 required to produce 672 cm³ H2O - measured at STP.