Question

Under the same reaction conditions, initial concentration of
1.386 mol dm⁻³ of a substance becomes half in 40 seconds
and 20 seconds through first order and zero order kinetics,
respectively. Ratio (k₁/k₀) of the rate constant for first order
(k₁) and zero order (k₀) of the reaction is –
(a) 0.5 mol⁻¹ dm³ (b) 1.0 mol dm⁻³
(c) 1.5 mol dm⁻³ (d) 2.0 mol⁻¹ dm³

Answer 1

Answer:

t

1/2

=

k

1

0.693

, t

1/2

=

2k

0

a

0

40=

k

1

0.693

, 20=

2k

0

1.386

=

k

0

0.693

40

20

=

0.693/k

1

0.693/k

0

=

k

0

k

1

k

0

k

1

=0.5

moldm

−3

sec

−1

sec

−1

=0.5mol

−1

dm

3