Question

Under the same reaction conditions, initial concentration
of 1.386 mol dm- of substance becomes half in
40 seconds and 20 seconds through first order and zero
ki
order kinetics, respectively. Ratio of the rate
ko
constants for first order (k,) and zero order () of the
reaction is
(1) 0.5 mol ^-1dm^3
(2) 1.0 mol ^dm^-3
(3) 1.5 mol dm^-3
(4) 2.0 mol^-1dm^-3​

Answer 1

Answer:

ANSWER

The given reaction is:

2N

2

O

5

⟶4NO

2

+O

2

The unit of rate constant indicates its first-order reaction.

Rate=K[N

2

O

5

] (Rate Law)

where K= Rate constant

Given that,

K=3×10

−5

sec

−1

Rate=2.4×10

−5

molL

−1

s

−1

Putting the given values in rate law:-

2.4×10

−5

=3.0×10

−5

[N

2

O

5

]

⇒

10

8

=[N2 O5 ]

⇒[N 2O 5 ]=0.8 molL ^−1