Question

under what condition a body on inclined smooth plane surface has an acceleration of 4.9m/s
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Answer 1

From the free body diagram shown in the fig. we can understand that the force acting on the body causing it falling down along the inclined plane is nothing but $\sf{mg\sin\theta,}$ and so the acceleration is $\sf{g\sin\theta.}$

So,

$\longrightarrow\sf{g\sin\theta=4.9}$

$\longrightarrow\sf{9.8\sin\theta=4.9}$

$\longrightarrow\sf{\sin\theta=\dfrac{4.9}{9.8}}$

$\longrightarrow\sf{\sin\theta=\dfrac{1}{2}}$

$\Longrightarrow\sf{\underline{\underline{\theta=30^{\circ}}}}$

Thus the acceleration of the body on a smooth inclined plane surface will be 4.9 m/s² if the angle of inclination is 30°.

Answer 2

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