under what condition oxidation of hydrocarbon become combustion reaction
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Oxidation reaction involves loss of electrons/addition of oxygen/removal of hydrogen. 1.Oxidation reaction canbe called as combustion reaction only when they release energy in the form of heat, light etc. ... Generally allhydrocarbons show the property ofcombustion oxidation reaction.
shubhamdevrani:
give examples
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Methane is oxidized to carbon dioxide…an EIGHT electron oxidation…
CH4(g)+2H2O(l)→CO2+8H++8e−CH4(g)+2H2O(l)→CO2+8H++8e−
And zerovalent dioxygen is reduced to O(−II)O(−II)in water….
1/2O2+2H++2e−→H2O1/2O2+2H++2e−→H2O
And so we take ONE of the former, and add it to FOUR of the latter to eliminate the electrons as virtual particles of convenience…
CH4(g)+2H2O(l)+2O2(g)+8H++8e−→CO2+8H++8e−+4H2OCH4(g)+2H2O(l)+2O2(g)+8H++8e−→CO2+8H++8e−+4H2O
And we cancel away…
CH4(g)+2O2(g)→CO2(g)+2H2O(l)
CH4(g)+2H2O(l)→CO2+8H++8e−CH4(g)+2H2O(l)→CO2+8H++8e−
And zerovalent dioxygen is reduced to O(−II)O(−II)in water….
1/2O2+2H++2e−→H2O1/2O2+2H++2e−→H2O
And so we take ONE of the former, and add it to FOUR of the latter to eliminate the electrons as virtual particles of convenience…
CH4(g)+2H2O(l)+2O2(g)+8H++8e−→CO2+8H++8e−+4H2OCH4(g)+2H2O(l)+2O2(g)+8H++8e−→CO2+8H++8e−+4H2O
And we cancel away…
CH4(g)+2O2(g)→CO2(g)+2H2O(l)
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