underline the objects in these sentences and state whether they are direct (D)or indirect(I).
7.We found the photographs.
8.Chitra kept the pen on the table.
9.Ashish brought some biscuits for his mother.
10.Ben listened to the story with great attention.
Answers
Explanation:
(i)
2x
1
+
3y
1
=2
3x
1
+
2y
1
=
6
13
Lets assume
x
1
=p and
y
1
=q, both equations will become
2
p
+
3
q
=2
⇒3p+2q=12 ... (A)
3
p
+
2
q
=
6
13
⇒2p+3q=13 ...(B)
Multiply (A) by 3 and (B) by 2, we get
9p+6q=36
4p+6q=26
Subtracting these both, we get
5p=10
⇒p=2
⇒x=
p
1
=
2
1
∴q=
6
26−8
=3
⇒y=
q
1
=
3
1
(ii)
x
2
+
y
3
=2
x
4
−
y
9
=−1
Lets assume
x
1
=p and
y
1
=q, both equations will become
2p+3q=2 ...(A)
4p−9q=−1 ...(B)
Multiply (A) by 3, we get
6p+9q=6
4p−9q=−1
Adding these both, we get
10p=5
⇒p=
2
1
⇒ x=
p
2
1
=4
∴q=
3
1
⇒y=
q
2
1
=9
(iii)
x
4
+3y=14
x
3
−4y=23
Lets assume
x
1
=p, both equations become
4p+3y=14 ...(A)
3p−4y=23 ...(B)
Multiply (A) by 4 and (B) by 3, we get
16p+12y=56
9p−12y=69
Adding these both, we get
25p=125
⇒p=5
⇒x=
p
1
=
5
1
⇒y=−2
(iv)
x−1
5
+
y−2
1
=2
x−1
6
−
y−2
3
=1
Lets assume
x−1
1
=p and
y−2
1
=q, both equations become
5p+q=2
6p−3q=1
Multiply (A) by 3, we get
15p+3q=6
6p−3q=1
Adding both of these, we get
21p=7
⇒p=
3
1
⇒ x=4
∴q=
3
1
⇒ y=5
(v)
xy
7x−2y
=5
⇒
y
7
−
x
2
=5
xy
8x+7y
=15
⇒
y
8
+
x
7
=15
Let t=
x
1
and r=
y
1
equation will be
7r−2t=5;8r+7t=15
On solving we get
t=1r=1
∴x=1andy=1
(vi)
Dividing both side by xy then we have
y
6
+
x
3
=6;
y
2
+
x
4
=5
Let t=
x
1
andr=
y
1
equation will be
6r+3t=6;2r+4t=5 on solving we get
t=1r=
2
1
∴x=1andy=2
(vii)
Let t=
x+y
1
andr=
x−y
1
then equation will be
10t+2r=4;15t−5r=−2 on solving we have
t=
5
1
andr=1
∴x+y=5andx−y=1
Hence, x=4,y=1
(viii)
Let t=
3x+y
1
andr=
3x−y
1
then equation will be
t+r=
4
3
;
2
t
−
2
r
=
8
−1
On solving we have
t=
4
1
andr=
2
1
∴3x+y=4and3x−y=2
Hence, x=1,y=1
7. Direct - photographs
8. Indirect - Pen on the table
9. Indirect- biscuits for his mother
10. Direct- Story
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