Question

underoot ( 1+sin A)² (1-sinA)² = Sec A +Tan A
Please solve this problem​

Answer 1

Step-by-step explanation:

√((1+sinA)^2 (1-sinA)^2) = secA + TanA

√((1 - sinA^2)^2) = secA + sin A /cos A

cosA ^2 = 1/cosA + sinA / cosA

cosA^2 = (1+sinA)/cosA

cosA^3 = 1 + sinA

after this, it can't be solved because there is no formula to solve it to get value of A,

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