Question

underoot 5 + underoot 3 upon underoot 5 - underoot 3 = a+b underoot 15
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Answer 1

Step-by-step explanation:

√5+√3/√5-√3=a+b√15

then multiple of opposite

√5+√3/√5-√3×(√5+√3)/√5+√3)=a+b/√15

(√5+√3)^2/(√5^2-√3^2)=a+b/√15

25+9+2×√5×√3\(5-3)=a+b/√15

34+2√15/2