underoot6+underroot6+underoot6
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love dis question !
Lol . Read on for the answer , not a joke . :D
Since it cms infinite no. Of times , even if we remove one sq. Rt of 6 , it wont matter .
Let the equation be equal to x .(i'll just be writing 6 for sq. Rt of 6)
(6 +(6+ . . .) = x
So , we can also write it as
(6 + x)^1/2 = x
Squaring both sides ,
6+x = x^2
X^2 -x -6=0
Solving it , we get x= 3 or -2
:)
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underoot18 is the answer
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