Math, asked by ishank7122, 2 months ago

underot 1+sin^/1-sin^ = 1 + sin  cos 

Answers

Answered by rraghu3056
0

Answer:

answer me please answer is no longer have to be a good day

Answered by ravi2303kumar
0

Answer:

(secθ+tanθ)²

Step-by-step explanation:

\frac{1+sin\theta }{ 1-sin\theta }

= \frac{1+sin\theta }{ 1-sin\theta } * \frac{1+sin\theta }{ 1+sin\theta }

= \frac{(1+sin\theta)^2 }{(1-sin\theta) (1+sin\theta)  }

= \frac{(1+sin\theta)^2 }{(1^2-sin^2\theta)}

= \frac{(1+sin\theta)^2 }{cos^2\theta}

= [\frac{1+sin\theta}{cos\theta}] ^2

= (secθ+tanθ)²

Similar questions