Math, asked by vandu14sharma, 8 months ago

Underroot 1+ sin A / 1-sin A = tan A + sec A​

Answers

Answered by Shanmukh11
2

Answer:

 \sqrt{ \frac{1 +  \sin(x) }{1 -  \sin(x) } }

 \sqrt{ \frac{{sin}^{2} \frac{x}{2} +  {cos}^{2} \frac{x}{2} + 2 \sin( \frac{x}{2})  \cos( \frac{x}{2} ) ) }{{sin}^{2} \frac{x}{2} +  {cos}^{2} \frac{x}{2}  -  2 \sin( \frac{x}{2})  \cos( \frac{x}{2} ) )} }

 \sqrt{ { (\frac{ \sin( \frac{x}{2} ) +  \cos( \frac{x}{2} )  }{ \sin( \frac{x}{2}   )  -  \cos( \frac{x}{2} ) } )}^{2} }

 \tan( \frac{\pi}{4}  + x)

 \tan(x)  +  \sec(x)

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