Question

underroot 20 on numberline
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Answer 1

Answer:

To locate √10 on number line follow the steps.                let 3cm = 1 unit

1] √10 = √3²+1²

2]draw a number line OC such that OA=AB=OC=1 unit

3] draw a perpendicular line from C of 1 unit [as √10 = √3²+1² ] and name the point as C

4] join O and C  it will form a triangle 

       by pythagoras theorem  

           OC = √10

           now taking the radius of OC in compass draw an arc touching the number line . 

and that point will be   √10 .

Answer 2

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First, we can estimate what √20 is by noticing that it lies between 4 and 5; since 42=16 and 52=25

Pythagoras’ Theorem states that in a right triangle with sides a, b and c (c being the hypotenuse); the equality a2+b2=c2 holds

Notice that 20=42+22

Therefore, √20 is the hypotenuse of a right triangle with other sides 4 and 2.

Start off at (0,0) on the cartesian plane (where the x-axis is the number line). Construct a triangle with base OB, such that O (0,0) and B(2,0) and height OC such that C(0,4). Join the length BC, which will have a length of √20.

Now, take a compass and make the radius of the circle to be constructed BC. Then, place the compass at the origin, and cut the length onto the positive x-axis. This will give you the position of √20.

Hope it helps you.