Question

underroot 3+underroot 2 upon underroot 3+underroot 2=a+b underroot 6​

Answer 1

Your question was :

$\frac{ (\sqrt{3} + \sqrt{2}) }{ (\sqrt{3} + \sqrt{2}) } = (a + b) \times \sqrt{6}$

• Rationalise the denominator on LHS
• Equate it to RHS
• Solve the equation.
• Find values of a and b

Mark Brainliest

Follow Me