Question

underroot 40+underroot 9 underroot 81​

Answer 1

√40+√9(√81)

=√2^2×10 +3(9)

=2√10 +27

= 27+2√10

Answer 2

For example, the square roots of 9 are -3 and +3, since (-3)2 = (+3)2 = 9. Any nonnegative real number x has a unique nonnegative square root r; this is called the principal square root .......... For example, the principal square root of 9 is sqrt(9) = +3, while the other square root of 9 is -sqrt(9) = -3.

AND

81=9⋅9 then the square root of √81=9

AND

Square root of 40 in radical form is √40. √40 = √10*2^2 = 2√10. Hence √40 represented in simplest radical form is 2√10.