underroot 61 on a number line with steps of construction. urgent.
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YaminiSahib:
by which method
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underoot of 61 on a number line is as follows;
this is the rough drawing that I've made please you make it properly.
Steps of construction
1-draw a line OA of 61 cm
2-Extand oa by 1 cm and mark it as B
3-Bisect 0B(you need to find the mid point of line segment OB by bisection)mark it as C
4-with AC as radius keep the compass at point C and draw a semicircle (remember the two points of the semicircle should exactly touch A and B or else it would be wrong)
5-construct a perpendicular at point A(perpendicular means 90 degree angle)the point that would be touching at the semicircle mark it as D
6-Draw another line segment(I've not drawn it longer because I din't have space but you please draw it atleast till somewhere around 32 because half of 61 lies above 30.or try experimenting different lengths with the next step)
7-take AD as the radius and draw an arc on the number line this would be underoot 61
this is the rough drawing that I've made please you make it properly.
Steps of construction
1-draw a line OA of 61 cm
2-Extand oa by 1 cm and mark it as B
3-Bisect 0B(you need to find the mid point of line segment OB by bisection)mark it as C
4-with AC as radius keep the compass at point C and draw a semicircle (remember the two points of the semicircle should exactly touch A and B or else it would be wrong)
5-construct a perpendicular at point A(perpendicular means 90 degree angle)the point that would be touching at the semicircle mark it as D
6-Draw another line segment(I've not drawn it longer because I din't have space but you please draw it atleast till somewhere around 32 because half of 61 lies above 30.or try experimenting different lengths with the next step)
7-take AD as the radius and draw an arc on the number line this would be underoot 61
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