Question

Underroot 7 raised to 2x+6 is equal to 7 raised to 6.find the value of x

Answer 1

Answer:

$\sqrt{ {7}^{2x + 6} } = {7}^{6 } \\ squaring \: on \: both \: sides \\ {7}^{2x + 6} = { ({7}^{6} )}^{2} \\ {7}^{2x + 6} = {7}^{12} \\ 2x + 6 = 12 \\ 2x = 12 - 6 \\ 2x = 6 \\ x = \frac{6}{2} \\ x = 3$