Underwhat conditions a reaction be spontaneous if both h and s are positive
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Answer:
Explanation:
Let us consider the equation for gibbs free energy
ΔG=ΔH−TΔS
Where,
δH is enthalpy change (KJmol
−1
)
T is absolute temperature (K)
ΔS is entropy change (JK
−1
)
For a reaction to be considered spontaneous ΔG<0
Therefore,
ΔH−TΔS<0
ΔH<TΔS
or
T>ΔHΔS
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