Question

Uneducated Ramu was working with a farmer.Ramu was given a task to count the coconuts .In the afternoon when farmer asked the count of coconuts,Ramu replied
When I counted 2each there was 1 balance.when counted with 3 each there was 1balance.when counted 4each there was 1balance .when counted with 5each there was 1balance and finally when counted with 6 each there was 1 balance and I gave a last chance and counted with 7each there was no balance.Farmer was happy and noted down the count of coconuts so how many coconuts where there??

Answer 1

Answer:

301

Step-by-step explanation:

we will be using 'mod' division here.

.

Normal Division :

5 ÷ 2 = 2.5

Mod Division : [mod gives remainder insted of quotient]

5 mod 2 = 1

Let the total no. of Coconuts = x

Acc. to quez :

x mod 2 = 1

x mod 3 = 1

x mod 4 = 1

x mod 5 = 1

x mod 6 = 1

x mod 7 = 0

So the ans. should be a number multiple of 7.

for a easy solution we can find the answer with the help of number 5.

as you can see every multiple of 5 ends with either '0' or with '5'.

so if we divide any number with 5 and the remainder wanted to be 1 then the number should ends with either '1' or '6'.

but the number should not be end with '6' as then it will be completely divisible by 2.

so x is a number that is completely divisible by 7 an ends with 1

numbers of these types in the table of 7.

21, 91, 161, 231, 301 ....

in these numbers only 301 is the number that fulfill our requirements.