Question

uniform bar of length l meter is supported at its and end loader by a weight W kgf at its middle. In equilibrium, find the reaction R1 and R2 at the ends

Answer 1

For mechanical equilibrium, R1 + R2 = W 

For rotational equilibrium, R1(l/2) + W(0) -R2(l/2) = 0 => R1 = R2 

Therefore, R1 = R2 = W/2

Answer 2

Answer:

The reaction at the ends R1 = W/2 and R2 = W/2

Explanation:

since the body is in equilibrium

therefore , R1 + R2= W .......................( i )

clockwise moment = R1 × L/2

anticlockwise moment = R2 × L/2

According to principle of moments

anticlockwise moment = clockwise moment

R1 × L/2 = R2 × L/2

(R1 L)/2 = (R2 L)/2

(R1 L) / (R2 L) = 2/2

R1/ R2 = 1

R1= R2. .....................(ii)

substituting (ii) in (i)

R1 + R1 = W

2 R1 = W

R1 = W/2

since R1 is equal to R2

therefore, R2 = W/2

so, the reactions at R1 AND R2 is equal to W/2

hope this helps u

this is very simple and understandable way