Question

uniform chain of length 12 cm and mass 2 kg is lying on a smooth table and one third of its length is hanging vertically down over the edge of the table if g is acceleration due to gravity the work required to pull the only hanging part on to the table is take G is equal to 10 metre per second square​

Answer 1

Answer:

Work done to pull the hanging part of the chain up on the table is 0.133 J

Explanation:

Total mass of the chain is given as

m = 2 kg

Now we know that one third part of the chain is hanging downwards

So the length of the chain hanging downwards is

$L = \frac{12}{3} = 4 cm$

mass of the hanging chain is

$m = \frac{2}{3} kg$

now the work done to pull the hanging part up on the table is same as change in potential energy of the system of chain

so we will have

$W = mg\frac{L}{2}$

$W = (\frac{2}{3})(10)(0.04}{2}$

$W = 0.133 J$

#Learn

Topic : Work and potential energy

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