.
Uniform electric field of intensity 5 volt/m acts parallel to x
axis. A charge of 2C is moved from 0 to A (1,1), to B
(2, 1) and finally to D (3,0) in this field. Work done in this
process is :
(a) 60 joule
(b) 40 joule
(c) 30 joule
(d) zero
Answers
Answered by
3
Answer:
Total distance=3m
Potential=5×3
=15
W=V×Q
=18×2
=30J
Explanation:
Mark me as brainliest please
Similar questions