Uniform electric field of magnitude 100 V/m in space is directed along the the y=3+x.find the potential difference between the point A (3,1)and (1,3)
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Answered by
84
E = 100 V / m
y = 3 + x
Potential difference (V)
E = -dV /dr
dV = -Edr
dV = -100 ( 1 - 3) - 100 ( 3 -1)
dV = -100 + 300 -300 + 100
dV = 0 V
y = 3 + x
Potential difference (V)
E = -dV /dr
dV = -Edr
dV = -100 ( 1 - 3) - 100 ( 3 -1)
dV = -100 + 300 -300 + 100
dV = 0 V
Answered by
6
Answer:
0 V
Explanation:
Potential difference between A and B is
V BA = −Edx−Edy= −100(1−3)−100(3−1)=200−200=0V
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