Question

uniform rod of length L and mass M has two identical beach of negligible size each each of mass M which can slide serial along the rod initially to be at the centre of the rod and the system is rotating with angular velocity Omega not about an Axis perpendicular to the rod and passing through the midpoint of the rod there are no external forces when the heat reaches the end of the rod for the angular velocity of the system .....​

Answer 1

Answer:

Explanation:

The expression for strain energy is 1/2 × stress × strain.

The energy stored in a body is the strain energy, and the per unit volume is strain energy density, when a work is done on it by an external force to stretch or deform the body.

Strain energy = U = 0.5 Fl,  where f is external force applied to produce an extension 'i.

The strain energy density, u = U/V = (0.5 F l)/V

or u = 1/2 F/A l/L where A is the area and L is the length of the body before the external force is applied V = AL)

or u = 1/2 × stress × strain

Thus the energy density of a strained wire or the potential energy per unit volume of a stretched wire is derived.

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