Question

uniform sphere has a radius 0.1 m and density 6×10 rest to 3 find its moment of inertia about a tangent to a surface​

Answer 1

volume of sphere = (4×π×r^3)/3 = 4.18879 × 10^-3

Mass of sphere = volume × density

= 4.18879×10^-3 × 6×10^3

= 25.13274 kg

moment of inertia about a tangent to surface

= (7×mass of sphere×r^2) / 5

= 0.3518 kg-m^2