Question

uniform string of length 1.5m has two successive harmonics of frequen 70H_{2} and 84H_{z} . The speed of the wave in the string ( nm/s) is​

Answer 1

Answer:

42m/s

Explanation:

Fundamental frequency of string = GCF= GCF of the successive harmonics of frequencise 70 Hz and 84 Hz ∴∴ n=14Hzn=14Hz ⇒⇒ v2l=1.4v2l=1.4 ⇒⇒ v=2×1.5×14v=2×1.5×14 =42m/s