Question

uniform uniform disc of radius 20 cm and mass 2 kg can rotate about a fixed Axis through the centre and perpendicular to its plane a massless cord is around along the rim of disc uniform force of 2 newton is applied on cord tangential acceleration of a point on the rim of a disc will be

Answer 1

Hii dear,

◆ Answer-
at = 2 m/s^2

◆ Explaination-
# Given-
F = 2 N
r = 20 cm = 0.2 m
m = 2 kg

# Solution-
M.I. of disc with axis in centre and perpendicular to plane is-
I = 1/2 m × r^2
I = 1/2 × 2 × (0.2)^2
I = 0.04 kgm^2

Torque produced at the rim is
τ = F × r
τ = 2 × 0.2
τ = 0.4 Nm

Angular acceleration will ne
α = τ / I
α = 0.4 / 0.04
α = 10 rad/s^2

Tangential acceleration is
at = α × r
at = 10 × 0.2
at = 2 m/s^2

Hope that helps you...