Question

Uniform wire of resistance 50 ohms is melted and recast into a wire of length half of the original what would be the resistance of the new formed

Answer 1

Answer:

50/4 = 12.5 ohm.

Explanation:

Length is half so, Area of cross-section is doubled.

Earlier,

Length = L

Area Of cross-section = A

New,

Length = L/2

Area od cross-section = 2A

Now, R' /R = L/2/2A × A/L

R'/50= 1/4

R' = 50/4

R' = 12.5