Question

UNIT
(2)
S
1. Find the length of a chord, 5 cm away from the centre
of a circle of radius 13 cm.
2. In the figure, 0 is the centre of
the circle. The perpendiculars
drawn to the sides of a
E
pentagon OP, OQ, OR, OS
and OT are equal. Prove that
ABCDE is a regular
pentagon
IC С
0
Q
B (3)
AP
hord at a distance of 52 cm from the​

Answer 1

Answer:

Let AB be a chord of a circle with centre O and radius 13 cm. Draw OL⊥AB. Join OA.

Here, OL=5 cm,OA=13 cm.

In right triangle OLA,

OA

2

=OL

2

+AL

2

13

2

please =5

2

+AL

2

AL

2

=144

AL=12

Since the perpendicular from the centre to a chord bisects the chord. Therefore,

AB=2AL=2×12=24 cm

solution

Step-by-step explanation:

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