unit digit in (784) 126+(784) 127
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Unit digit of 4square is 6
So, unit digit in (4sq)63 is 6
∴ Unit digit of (784)126 = Unit digit in 4¹²⁶, which is 6
Unit digit in 4127 = Unit digit in (4¹²⁶× 4) = Unit digit in (6 × 4), which is 4
∴ Unit digit in (784)127 is 4
Hence, unit digit of [(784)126 + (784)127] = Unit digit of (6 + 4) = Unit digit of 10, which is 0
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