Question

unit digit of 11^2015+12^4027

Answer 1

•••To find unit digit in (xyz)^n•••
(where z is unit digit) [also works for more than 3 digits]

••••••Method:
Divide n by 4 and check Remainder.

Case (i)
n is a multiple of 4 i.e., rem=0
check if z is even or odd
z- odd => unit digit= 1
z- even=> unit digit= 6

Case (ii)
Remainder= 1
unit digit = z

Case (iii)
Remainder = 2
unit digit = unit digit of (z)²

Case (iv)
Remainder = 3
unit digit = unit digit of (z)³


Note that when z is 5, then last digit is always 5 irrespective of n.





|||||||||||Coming to your question||||||||||||

11^2015 + 12^ 4027

find unit digits in two terms

2015/4 rem=>3
unit digit in product is same as cube of unit digit in base
1³ = 1


4027/ rem=> 3
2³ = 8

add both terms
1+8= 9

Thus 9 is the last digit of what you 've asked.

Check this ::
Divisibility rule of 4 will be helpful
Remember that!


Hope it helps
:)
Mark brainliest ifyou find this helpful