unit digit of (2017)^2018
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2017^1=2017=***7
2017^2=2017×2017=********9
2017^3=**********9×2017=**********3
2017^4=*********3×2017=***********1
2017^5=*********1×2017=************7
2017^6=**********7×2017=**********9
we found that in the result of 2017^1 to 2017^4 ,again in 2017^5 to 2017^8 unit place contains the digits 7, 9 , 3 , 1 repeatedly by order of four .
we are to calculate 2017^2016 only unit place digit .
2017^2=2017×2017=********9
2017^3=**********9×2017=**********3
2017^4=*********3×2017=***********1
2017^5=*********1×2017=************7
2017^6=**********7×2017=**********9
we found that in the result of 2017^1 to 2017^4 ,again in 2017^5 to 2017^8 unit place contains the digits 7, 9 , 3 , 1 repeatedly by order of four .
we are to calculate 2017^2016 only unit place digit .
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