Unit digit of the surface area of a chalk box, whose length, breadth and height are 16 cm, 8 cm and 6 cm respectively, is?
Answers
Answered by
5
l=16cm
b=8cm
h=6cm
SA=2(l*b+b*h+h*l)
=2(16*8+8*6+6*16)
=2(128+48+96)
=2(272)
=544cm
b=8cm
h=6cm
SA=2(l*b+b*h+h*l)
=2(16*8+8*6+6*16)
=2(128+48+96)
=2(272)
=544cm
Similar questions