Unit's digit of a two-digit number is 5 less than its
ten's digit. The sum of the digits is 3 of the number.
Find the number
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Answer:
let the tens digit be x
ones digit is 10x-5
10x+10x-5=3
20x=8
x=8/20
x=2/5
so
Number=10×2/5+10×2/5-5
number=4+-1
3
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