Question

Unit's digits of a 2 digit number is 5 more than the ten's digit, and if we put the digits of the number in reverse order, the new number is 4 less than twice the original number. The number is

Answer 1

let xy be the number then then y=X+5
yx+4=2xy
we can write this as
10y+X+4=2(10x+y) by solving we get
X=4
and y=9 number is 49

Answer 2

$\huge\purple { Step\ by\ step\ explanation }$

Let, the tens digit of the number is x

then,

unit digit of the number = x+5

Original number = 10*x+(x+5)

= 10x+(x+5)

= 11x+5

Number obtained by reversing the digit

= 10*(x+5)+x

= 10x+50+x

= 11x+50

According to question

{2(11x+5)}-4 = 11x+50

(22x+10)-4 = 11x+50

22x+6 = 11x+50

22x-11x = 50-6

11x = 44

x = 44/11

x = 4

Hence,

The original number

= 11x+5

= (11*4)+5

= 44+5

= 49

$<marquee>$

$\mathfrak\purple { ... I\ Hope\ Suzy\ Answer\ Will\ Help\ You }$

$\mathfrak\purple { Make\ Me\ Brainlist }$
♥️♥️♥️♥️