Chemistry, asked by Anonymous, 3 months ago

units
. Analyse the following reactions and identify incorrect
statements where X and Y are two different aldohexoses
and X is a ketohexoses.
Disaccharide (A)
+Z
Disaccharide (B)
H.O/H® 2X
H,O/H X+Y
Disaccharide (C)
X+Y
(a) A, B and C are reducing sugars
(b) B and C have C, -C, glycosidic linkage between two
monosaccharide units.
(c) The two monosaccharide units of diasaccharide Care
C, epimers
(d) All the three diasaccharides undergo mutarotation
(1) a but not b, c and d (2) b and c but not a and d
(3) d but not a, b and c (4) a and d but not b and c​

Answers

Answered by prakhar941230
0

Answer:

An aldohexose is a hexose with an aldehyde group on one end. The aldohexoses have four chiral centres for a total of 16 possible aldohexose stereoisomers (24). Of these, only three commonly occur in nature: D-glucose, D-galactose, and D-mannose.

A ketohexose is a ketone-containing hexose (a six-carbon monosaccharide). The most common ketohexoses, each of which represents a pair of enantiomers (D- and L-isomers), include psicose, fructose, sorbose, and tagatose.

Ribose is an aldopentose, which means a pentose sugar with an aldehyde functional group in position one

Erythrose is a tetrose saccharide with the chemical formula C4H8O4. It has one aldehyde group, and so is part of the aldose family.

Explanation:

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