Question

units digit in the 99th number in the sequence 1 3 9 27​

Answer 1

Answer:

Note that the series can be written as

30, 31, 32, 33....... =

34n, 34n + 1, 34n + 2,, 34n + 3........ for n = 0, 1, 2, 3 ..........

And the last digit has the repeating pattern

1, 3, 9, 7 ...........

So....the 99th term is 398 = 34(24) + 2 which will end in 9

so l help you